16x^2+28x+30=42

Solution for 16x^2+28x+30=42 equation:

16x^2+28x+30=42

We move all terms to the left:

16x^2+28x+30-(42)=0

We add all the numbers together, and all the variables

16x^2+28x-12=0

a = 16; b = 28; c = -12;
Δ = b2-4ac
Δ = 282-4·16·(-12)
Δ = 1552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1552}=\sqrt{16*97}=\sqrt{16}*\sqrt{97}=4\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{97}}{2*16}=\frac{-28-4\sqrt{97}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{97}}{2*16}=\frac{-28+4\sqrt{97}}{32}
$